;+
;FUNCTION: mvn_lpw_r_block16
;PURPOSE:
; Decomutater for the compression for block=16 reading the datafile as WORD
; This routine is called by the mvn_lpw_r_header.pro
;
;USAGE:
; output=mvn_lpw_r_block16(data,ptr,nn_e,mask16,bin_c,index_arr,output)
;
;INPUTS:
; data this should be the unsigned array of the read in file
; ptr this is which element to start with in the data array and updated ptr
; nn_e this is which bit to start with based on element 'ptr' and array 'data' and update nn_e
; mask16 this is to convert the value in the array 'data' to a 16-bit binary array
; bin_c this is an index array to convert the bit's to a integer
; index_arr this is an index array
; output the result of the read resultinf in an array with values form the array 'data'
; the size of output depends on the size initiated, mod of 16
;
;OUTPUTS:
; hsbm - array of [1024,*] or [4096,*], one column for each hunk
; p - number of hunks, intended to go into variable p20, p21, or p22 in mvn_lpw_r_header
;
;KEYWORDS:
;
;
;CREATED BY: 2011
;FILE: mvn_lpw_r_block16.pro
;VERSION: 2.0
;;LAST MODIFICATION: 2012 April 24 by: Laila
; ;140718 clean up for check out L. Andersson
;-
function mvn_lpw_r_block16,data,ptr,nn_e,mask16,bin_c,index_arr,arr_size,edac_on
;
;-------------- LAilas try to uncompress SECTION 8.9 data compression---------------
; 32 blocks of 16 bits or 16 blocks of 32 bits (20 bits sign estended)
; first value is the absolute the following points are the fluctuation, PADING might have been used
;EUV and AVG have both 16 and 32 sample blocks (swp_i 16 and swp_v 32)
; broken into multiple 64 byte compression blocks
;32 block
;first 32 block start with 16 bit then ND 7 bit number last 31 is 6 bit 16 + 7 + 31 x 6 = 209 ->27*8 words=216
;the 7 bit = P2 P1 P0 D3 D2 D1 D0 where ND-1= D3D2D1D0 EDAC=P2P1P0 and P2 =D1xorD2xorD3; P1=D0xorD2xorD3; P0=D0xorD1xorD3
;second 32 block start with 16 bit followed by 7 bit number this continues until ND =16
;16 block
;first 16 block starts with 20 bit sample followed ND as 9 bits then 16 deltas of length ND
;the 9 bits are P3P2P1P0D4D3D2D1D0 EDACbits then ND-1bits P3=D4 and P2 =D1xorD2xorD3; P1=D0xorD2xorD3; P0=D0xorD1xorD3xorD4
;second 16 block with 20 bit sample folloewd with 9 bit ND ND - 20 delta is disable
;For this one it is as follows:
;I1(0-15) I1(16-31) I1(32-47) I1(48-63) I1(64-79) I1(80-95) I1(96-111) I1(112-127) V2(0-31) V2(32-63) V2(64-95) V2(96-127)
edac_on=0
n_loops=arr_size/16 ; how many time the loop below createin 16 values at a time needs to be operated
output=fltarr(arr_size)
reject=0
tmp0=intarr(16) ; newfile_signed is 16 bit array
temp_16=fltarr(16) ; this is the number of points in this 16*8 = 128 total number of values in each sweep
ptr_size=(20+9+20*15)/8 < ((n_elements(data)-ptr)-1)
IF (ptr+ptr_size)/8 LE n_elements(data) THEN $
for nii = 0,n_loops-1 do begin ; 8 sets
bin=intarr(16) ; newfile_signed is 16 bit array needs to be reset for each loop
ptr_size=(20+9+20*15)/8 < ((n_elements(data)-ptr)-1)
ptr_end=long(ptr+ptr_size) ; < (n_elements(data)-1) ;(length2[i]-len_offset-4)/8 +1 ; this should be based on the (length2[i]-len_offset-4)
tmp=data[ptr:ptr_end]
bin[*]=mask16[tmp[0],*] ; manuall change
ptr_size=(20+9+20*15)/8 < ((n_elements(data)-ptr)-1)
for ui=1,ptr_size-1 do begin ; remove this begin end .....
tmp0[*]=mask16[tmp[ui],*]
bin=[bin,tmp0]
endfor
nd_1=bin[24+nn_e]*16+bin[25+nn_e]*8+bin[26+nn_e]*4+bin[27+nn_e]*2+bin[28+nn_e] ; should be first 4 EDAC bits then 5 bit which is ND-1
; bin xor bin xor bin == (bin+bin+bin) mod 2
if bin[20+nn_e] NE bin[24+nn_e] AND $ ;P3 = D4
bin[21+nn_e] NE (bin[27+nn_e]+bin[26+nn_e]+bin[25+nn_e]) mod 2 AND $ ;P2 = D1 xor D2 xor D3
bin[22+nn_e] NE (bin[28+nn_e]+bin[26+nn_e]+bin[25+nn_e]) mod 2 AND $ ;P1 = D0 xor D2 xor D3
bin[23+nn_e] NE (bin[28+nn_e]+bin[27+nn_e]+bin[25+nn_e]+bin[24+nn_e]) mod 2 THEN edac_on=1 ;P0 = D0 xor D1 xor D3 xor D4
; Print,' Warning the EDAC and ND values did not agree in this 16 block compression ',bin(nn_e+0) ;use this later to fluch this package
if bin[20+nn_e] NE bin[24+nn_e] AND $ ;P3 = D4
bin[21+nn_e] NE (bin[27+nn_e]+bin[26+nn_e]+bin[25+nn_e]) mod 2 AND $ ;P2 = D1 xor D2 xor D3
bin[22+nn_e] NE (bin[28+nn_e]+bin[26+nn_e]+bin[25+nn_e]) mod 2 AND $ ;P1 = D0 xor D2 xor D3
bin[23+nn_e] NE (bin[28+nn_e]+bin[27+nn_e]+bin[25+nn_e]+bin[24+nn_e]) mod 2 THEN reject=reject+1 ;P0 = D0 xor D1 xor D3 xor D4
; 2^n calculated where bin_c(n)=2^n -- bin is the long array with 1's and 0's -- Uses the first 20 to get the value - should the first be the sign?
; to flip a bit == (1-a)*(1+1)
temp_16[0] = (1-bin[0+nn_e])* total( bin[1+nn_e:19+nn_e] *bin_c[18-index_arr[0:18]])- $ ;if the value is positive
bin[0+nn_e] *(total((1-bin[1+nn_e:19+nn_e])*(1+bin[1+nn_e:19+nn_e])*bin_c[18-index_arr[0:18]])+1) ;if the value is negative
nd=nd_1+1 ; the recorded information is ND-1
nn_g=9+20+nn_e ; where the second number (the delta) starts with respect to ptr
IF nn_g+14*nd+nd-1 GE n_elements(bin) then nd=(n_elements(bin)-nn_g)/15
IF nd EQ 1 then $ ;
for ii=0,14 do temp_16[ii+1]=temp_16[ii]+ $ ; first value is the sign, then sum over the other nd-1 elements
0 - $ ; if it is positive
bin[nn_g+0+ii*nd] $ ; if it is negative
ELSE $ ;nd EQ 20
IF nd EQ 2 then $
for ii=0,14 do temp_16[ii+1]=temp_16[ii]+ $ ; first value is the sign, then sum over the other nd-1 elements
(1-bin[nn_g+0+ii*nd])* bin[nn_g+ii*nd+1] -$ ; if it is positive
bin[nn_g+0+ii*nd] *((1-bin[nn_g+ii*nd+1])*(1+bin[nn_g+ii*nd+1])+1) $ ; if it is negative
ELSE $ ;if nd is not ==1,2
IF nd EQ 20 then $ ; ND == 20 decoding disable
for ii=0,14 do temp_16[ii+1]= $ ; first value is the sign, then sum over the other nd-1 elements
(1-bin[nn_g+0+ii*nd])* total( bin[nn_g+ii*nd+1:nn_g+ii*nd+19] *bin_c[18-index_arr[0:18]] ) -$ ; if it is positive
bin[nn_g+0+ii*nd] *(total((1-bin[nn_g+ii*nd+1:nn_g+ii*nd+19])*(1+bin[nn_g+ii*nd+1:nn_g+ii*nd+19])*bin_c[18-index_arr[0:18]] )+1) $ ; if it is negative
ELSE $ ; the rest not special cases
for ii=0,14 do temp_16[ii+1]=temp_16[ii]+ $ ; first value is the sign, then sum over the other nd-1 elements
(1-bin[nn_g+0+ii*nd])* total( bin[nn_g+ii*nd+1:nn_g+ii*nd+nd-1] *bin_c[nd-2-index_arr[0:nd-2]] ) -$ ; if it is positive
bin[nn_g+0+ii*nd] *(total((1-bin[nn_g+ii*nd+1:nn_g+ii*nd+nd-1])*(1+bin[nn_g+ii*nd+1:nn_g+ii*nd+nd-1])*bin_c[nd-2-index_arr[0:nd-2]] )+1) ; if it is negative
nn_e=(nn_g+nd*15) mod 16
ptr=ptr+floor(1.0*(nn_g+nd*15)/16) ; 20+9+nd*15 bit should one block contain and newfile_signed is a 16 bit array
output[nii*16+0: nii*16+15] = temp_16 ; this is just 1/8 of the points
endfor ELSE ptr= n_elements(data) ; change ptr if en od array has been reached
If reject GT 0 then output=output*0 ; there was an issue during this packet
return,output
end